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Class 10 Science Chapter 10 NCERT Solutions are structured in a comprehensive and presentable way to provide students with complete coverage of the topics and scientific terms which can help students in scoring well in their exams as well as gain perspective towards career goals.
Chapter 10 Class 10 Science is mostly about reflection and refraction of light. The main topics included consist of spherical mirrors, magnification, reflection, refraction and power of a lens. To provide simplification, Light Reflection and Refraction Class 10 Solutions include various diagrams, logical problems and detailed content in simple words. The topic Reflection of Light Class 10 refers to light waves bouncing off the surface of objects that do not have the capability of absorbing energy produced by radiation.
A surface of a pool, for example, will display clarity of surrounding objects when still. Whereas, all the rays would be scattered once a rock is thrown inside it preventing systematic reflection of light. Refraction of light Class 10, on the other hand, refers to the bending of light waves when it travels from a faster to a slower medium.
Images formed by lenses and our eyes exist due to this process. All the aforementioned topics are thoroughly explained under Chapter 10 Science Class 10 solutions by teachers having expertise in the subject.
Physics subject requires students to have a good grip on the basic understanding of the concepts. The normal weightage of the part as indicated by the most recent guidelines is 7 marks. In Ch 10 Science Class 10, students will get knowledge about refraction and reflection.
The refractive index of diamond is 2. This suggests that the speed of light in diamond will reduce by a factor 2. Define one dioptre of power of a lens?
Answer: One dioptre is the power Of a lens Of focal length 1m. Power of lens is defined as the reciprocal of its focal length. It is denoted by D.
A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the lens if the image is equal to the size of the object? Also find the power of the lens. The position of image should be double the focal length. Hence, the object should be at 2f. Find the power of a concave lens of focal length 2 m.
Which one of the following materials cannot be used to make a lens? Where should an object b. A spherical mirror and a thin spherical lens have each a focal length of 15 cm. The mirror and the lens are likely to be: a both concave b both convex c the mirror is concave, but the lens is convex d the mirror is convex, but the lens is concave Answer: a Both concave.
No matter how far you stand from a mirror, your Image appears erect. The mirror is likely to be a plane b concave c convex d Either plane or convex Answer: d Either plane or convex.
Question 6. Question 7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. For getting an erect image using a concave mirror, the object should be placed at a distance less than the focal length. The image formed will be virtual, enlarged and erect. Question 8. Name the type of mirror used in the following situations. Answer: a Concave mirror, to get powerful and parallel beams of light. Question 9. One half of a convex lens is covered with a black paper.
Answer: Yes, even when one half of the lens is covered with a black paper, complete image of the object will be formed. Take a convex lens and focus the light from a distant object onto a screen.
As expected an image sharp is formed at a distance equal to the focal length Cover the lower or the upper half of the lens and focus the light from the same object onto the same screen.
You will be able to get a sharp image again; however the brightness of the image will be less in the second case. The same effect w,ll be seen even if the lens is half covered with black strips. Question An object 5cm in length is held 25cm away from a converging lens of focal length 10 cm.
Draw a ray diagram and find the position, size and the nature of the image formed. It is real and inverted, and smaller in size than the object. How far is the object placed from the Pens?
An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Answer: This means that size of the image is equal to the size of the object.
An object 5. Find the position of the image nature and size. An object of size 7. At what distance from the mirror should a screen be placed, so that a sharp focused image can be obtained? Find the focal length of a lens of power Hold a highly polished steel spoon curved inwards close to your face and move it slowly away from your face.
What will you observe? When the spoon is at a small distance from the face such that, the object lies between pole and focus of concave mirror, so an enlarged and erect image of your face will be observed but as the spoon is slowly moved away from the face, the image becomes smaller and appears inverted. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be [NCERT] a plane b concave c convex d either plane or convex Answer: d Plane mirrors and convex mirrors always form the erect images.
The image formed by a concave mirror is observed to be virtual, erect and larger than the object. An object AB is placed in front of a convex lens at its centre of curvature as shown in figure below. Four students traced the path of light ray after refraction through the lens. Which one of them is correct?
The image formed is real and inverted. A spherical mirror and a thin spherical lens have each of a focal length cm. The mirror and lens are likely to be [NCERT] a both concave b both convex c mirror is concave and lens is convex d mirror is convex and lens is concave Answer: a The focal length is taken as negative for both concave mirror and concave lens.
Which of the following can make a parallel beam of light when light from a point source is incident on it? Under which of the following conditions, a concave mirror can form an image larger than the actual object? A light ray enters from medium A to medium Bas shown in the figure. So, it has greater refractive index and lesser velocity of light w. So, refractive index of medium B w.
Figure shows a ray of light as it travels from medium A to medium B. Beams of light are incident through the holes A and B and emerge out of box through the holes C � and D respectively, as Box shown in the figure. Which of the following could be inside the box? Therefore, a rectangular glass slab could be inside the box as the extent of bending of light ray at the opposite parallel faces AB air-glass interface and CD glass-air interface of the rectangular glass slab are equal and opposite.
This is why the ray emerges parallel to the incident ray. A beam of light is incident through the holes on side A and emerges out of the holes on the other face of the box as shown in the figure.
So, inside the box there must be a convex lens. Which of the following statement is true? Magnification produced by a rear view mirror fitted in vehicles [NCERT Exemplar] a is less than one b is more than one c is equal to one d can be more than or less than one depending upon the position of the object in front of it. Answer: a The convex mirror forms virtual, erect and diminished image of the object and rear view mirror also form same type of image.
Therefore, magnification m produced by a rear view mirror fitted in vehicles is less than one, i. Rays from the Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed, so that size of its image is equal to the size of the object? Therefore, focal length if of concave mirror is 15 cm. This is why the ray emerges are parallel to the incident ray. You are given water, mustard oil, glycerine and kerosene. In which of these media, a ray of light incident obliquely at same angle would bend the most?
Thus, glycerine is most optically denser and hence have the largest refractive index. Therefore, ray of light bend most in glycerine. How many images will be observed by him? Where should an object be placed in front of a convex lens to get a real image of the size of the object? Which of the following lenses would you prefer to use while reading small letters found in dictionary?
For better performance its focal length should be small. A concave mirror gives an erect image when an object is placed between its pole P and the principal focus F. Hence, to obtain an erect image of an object from a concave mirror of focal length 15 cm, the object must be placed anywhere between the pole and the focus i.
The image formed will be virtual, erect, and magnified in nature, as shown in the given figure. This is because concave mirrors can produce powerful parallel beam of light when the light source is placed at their principal focus.
That is why they are used to construct solar furnaces. Concave mirrors converge the light incident on them at a single point known as principal focus. Hence, they can be used to produce a large amount of heat at that point. The convex lens will form complete image of an object, even if its one-half is covered with black paper.
It can be understood by the following two cases. In this case, the rays of light coming from the object will be refracted by the lower half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the following figure. In this case, a ray of light coming from the object is refracted by the upper half of the lens.
Concept Insight: In case of the half covered lens, the number of rays used up to make the image on the other side of the lens will be reduced to half.
Concept Insight: Remember to use appropriate sign conventions while substituting the values in lens formula. The negative value of u indicates that the object is placed 30 cm in front of the lens.
This is shown in the following ray diagram. The positive value of v indicates that the image is formed behind the mirror. The positive value of magnification indicates that the image formed is virtual and erect. Concept insight - Correct interpretation of the signs are important. Object distance u is conventionally always taken as negative. Magnification produced by a mirror is given by,. It shows that the image formed by the plane mirror is of the same size as that of the object.
The positive sign shows that the image formed is virtual and erect. Concept Insight - Positive magnification corresponds to virtual and erect image. The numeral value of magnification indicates that the size of the image is that many times the size of the object. According to the mirror formula,. The positive value of magnification indicates that the image formed is virtual. The positive value of the image height indicates that the image formed is erect.
Therefore, the image formed is virtual, erect and smaller in size. Concept Insight - Write the given data in appropriate sign conventions. Then identify the unknown quantities that need to Ncert Solutions Class 10th Physics Chapter Light Quest be evaluated. Then put the formulae that are most suitable. The screen should be placed at a distance of 54 cm in front of the given mirror. The negative value of the image height indicates that the image formed is inverted.
Concept Insight - The interpretation of sign convention is the key here. The focal length is negative. Hence, it is a concave lens. Concept Insight Ncert Solutions Class 10th Physics Chapter Light Year - The value of the focal length should be written in metres when substituting in the formula:. Concept Insight: Positive focal length corresponds to convex lens and negative focal length corresponds to concave lens. Enter the OTP sent to your number Change.
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