Observe the steps to compute the median, median and mode as per the data presented in a Maths question. By learning Statistics, you will be able to find answers for real-life scenarios as well. Practise textbook questions to revise concepts like cumulative frequency, lower limit, upper limit etc. If you need more support materials to revise Statistics, explore our mock question papers, practice tests and other Class 10 resources. Let us find class marks x i for each interval by using the relation.
Now we may compute x i and f i x i as following. From the table, we may observe that So, the mean number of plants per house is 8. We have used here direct method as values of class marks x i and f i are small.
Let us find class mark for each interval by using the relation. Now taking as assured mean a we may calculate di, u i and f i u i as following. From the table we may observe that. Clearly, mean number of mangoes kept in a packing box is We have chosen step deviation method here as values of f i , d i are big and also there is a common multiple between all d i.
Now we may observe that -. Now we may observe that So, the mean literacy rate is Now taking 30 as assumed mean a we may calculate d i and f i d i as following. We may observe from the given data that maximum class frequency is 40 belonging to - intervals.
Now from the table, we may observe that So, mean monthly expenditure was Rs. We may observe from the given data that maximum class frequency is 10 belonging to class interval 30 - T have a teacher student ratio as So mean of data is Here the class width is not the same. There is no need to adjust the frequencies according to class intervals. Now given frequency table is of less than type represented with upper-class limits. As policies were given only to persons having age 18 years onwards but less than 60 years, we can define class intervals with their respective cumulative frequency as below.
The given data is not having continuous class intervals. We can observe that the difference between the two class intervals is 1. So, we have to add and subtract. Now continuous class intervals with respective cumulative frequencies can be represented as below.
From the table, we may observe that cumulative frequency just greater than is 29, belonging to Byjus Class 6 Maths Chapter 5 English class interval We can find cumulative frequencies with their respective class intervals as below -. Now we may observe that cumulative frequency just greater than is belonging to class interval - We can find cumulative frequencies with their respective class intervals as below.
Now we may observe that cumulative frequency just greater than is 76 belonging to the class interval 7 - Cumulative frequency just greater than is 19, belonging to class interval 55 - Enter the OTP sent to your number Change. Resend OTP. Starting early can help you score better! Avail Offer.
Ok Cancel. Ok Choose Chapter. Ok Choose Topic. Yes No. Choose Subjects. Choose Chapters. Chapter 14 - Statistics Exercise Ex. We may find class mark x i for each interval by using the relation. Daily pocket allowance in Rs.
We may find class mark of each interval x i by using the relation. Number of mangoes Number of boxes f i 50 - 52 15 53 - 55 56 - 58 59 - 61 62 - 64 25 We may observe that class intervals are not continuous. There is a gap of 1 between two class intervals. So we have to add to upper class limit and subtract from lower class limit of each interval. We may compute class marks x i as per the relation Now taking 30 as assumed mean a we may calculate d i and f i d i as following.
It represents that on an average the age of a patient admitted to hospital was As we may observe that maximum class frequency is 23 belonging to class interval 35 - It represents that maximum number of patients admitted in hospital were of From the data given as above we may observe that maximum class frequency is 61 belonging to class interval 60 - From the given data we may observe that maximum class frequency is 18 belonging to class interval - From the given data we may observe that maximum class frequency is 20 belonging to 40 - 50 class intervals.
So, we have to add and subtract to upper-class limits and lower class limits. Now continuous class intervals with respective cumulative frequencies can be represented as below Length in mm Number or leaves f i Cumulative frequency We may find cumulative frequencies with their respective class intervals as below Weight in kg No. So median of this data is We may observe that difference between two consecutive upper class limits is 2. Have an account? Sign In. Verify mobile number.
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Add to favourite Share Remove. Number of students f i. Number of cities f i. Number of patients f i. Expenditure in Rs. Number of families f i. Number of students per teacher. Monthly consumption in units. Number of consumers f i. Cumulative frequency. Number of policyholders f i. Cumulative frequency cf. Number or leaves f i. Number of lamps f i. Frequency f i. Number of letters. Number of surnames. Daily income in Rs upper class limits. Weight in kg upper class limits.
Number of students cumulative frequency. Weight in kg. Frequency f. Production yield lower class limits.
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