Direct Formula / Rule 1: Theorem: If the speed of the boat (or the swimmer) is x km/hr and if the speed of the stream is y km/hr then, while upstream the effective speed of the boat = (x - y)km/hr. Example: Question: Speed of a man is 8 km/hr in still water. If the rate of current is 3 km/hr, find the effective speed of the man upstream. Speed of Boat = y [ (t 2 + t 1) / (t 2 � t 1)] A man can row certain distance downstream in 2 hours and returns the same distance upstream in 6 hours. If the speed of stream is km/h, then the speed of man in still water is. = [ (6+2) / ()] = * (8/4) = * 2 = 3km/h. Jun 12, �� Upstream Speed = 15 + x. Downstream Speed = 15 � x. So, {30 / (15+x)} + {30 / (x)} = 4 ? (4 hours 30 minutes) ? { / (x2)} = 9/2. ? 9x2 = ?x2 = ?x = 5. Q 5. A boat is moving 2 km against the current of the stream in 1 hour and moves 1 km in .
This is the aptitude questions and answers section on "Boats and Streams Important Formulas" with explanation for various interview, competitive examination and entrance test. Solved examples with detailed answer description, explanation are given and it would be easy to understand.� If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then: Speed downstream = (u + v) km/hr. Speed upstream = (u - v) km/hr. Boats and Streams - Quantitative aptitude tutorial with easy tricks, tips, short cuts explaining the concepts. Online aptitude preparation material with practice question bank, examples, solutions and explanations. Video lectures to prepare quantitative aptitude for placement tests and competitive exams like MBA, Bank exams, RBI, IBPS, SSC, SBI, RRB, Railway, LIC, MAT. Very useful for freshers, engineers, software developers taking entrance exams. Learn and take practice tests!� Boats & Streams. Basic Terms used in the chapter: 1) Stream: The moving water of river is called as stream. Derivation of formula 8 (boats and streams). Let the speed of a man in still water = $x$ km/hr speed of the stream = $y$ km/hr. Assume he travels a distance $d$ km upstream and come back the same distance downstream, and total time taken = $t$ hours. Speed downstream $=(x+y)$ Speed upstream $=(x-y)$. Time taken to travel upstream $=\dfrac{d}{x-y}$ Time taken to travel downstream $=\dfrac{d}{x+y}$. Total time $=t$ $\dfrac{d}{x-y}+\dfrac{d}{x+y}=t\\ d(x+y)+d(x-y)=t(x+y)(x-y)\\ 2dx=t(x+y)(x-y)\\ 2dx=t(x^2-y^2)\\ d=\dfrac{t(x^2-y^2). }{2x}$.
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