Riverboat Problems
Boat speed 41 m/s Boat And Stream Problems In Tamil Unit River speed 20 m/s River width 20 m Can anyone help me? Show your work please. (=� Physics � 1 decade ago. Help with physics boat problems!!!? How far downstream will a boat aimed 31 degrees upstream land? Boat speed. 21 m/s. River speed. River Boat problems are related to relative velocity as observed by a moving or stationary observer. As an example, a motorboat in a river is moving in a river current - water that is moving with respect to an observer on dry land/or the bank. In. PDF | On Jun 6, , Helmi Abdullah published The Physics Problem Solver: The boat and the buoy in the river | Find, read and cite all the research you need on ResearchGate.� Problem A boat drove constantly above the water surface with a speed of 3m/s in the. direction of the current. If current velocity is 2m/s. Suppose that at t = 0, a buoy. falls. Once the boat moves m from the fall of the buoy, the pearahu reverses. direction. Determine where the buoy can be picked up by the skipper.

You want to paddle a boat straight across the Mississippi River. You are able to paddle the boat with a speed of 5. What direction, relative to the river bank, do you need to point the boat? How fast do you move relative to land? The actual motion of the boat relative to land is equal to the velocity of the boat through the water plus the velocity of the water. Think about carrying a bowl of water while a fish swims in that bowl. In other words, it is a math problem Boat Electrical Problems asking you to practice working with vector components.

If you thought of this as a vector component problem because you recognized that you are given one side and the hypotenuse of a triangle and asked for the other side and one angle, that is also great and will give you the same approach to the solution. Remember, vectors are added head to tail. The sum is the vector that goes from the tail of A to the head of B.

In this case, the three vectors form the sides and hypotenuse of a right triangle. So we do not need to divide vectors into components, we can just look at the four relations for a right triangle:. Relation 1. You need to point your boat at an angle of 78 0 from the bank of the river as shown in the picture 12 0 from straight across, into the current in order to go straight across the river. Scroll down to find the speed of the boat relative to land.

The boat moves at a speed of 5. As shown in the equation and discussed in the identification of the problem, the actual motion of the boat relative to land v b depends both on how you row the boat v bw and on the current that carries the water downstream vc. If you want a path that is straight across the river as specified in this problem, you need to point the boat at an angle into the current so that it is not carried downstream.

The speed at which you row a boat is the speed at which it moves through the water, not the resulting speed relative to land. If a fish can swim through the water in the bowl at a certain speed, its motion relative to the floor is that velocity plus any motion of the bowl. Therefore, it is v bw and not v b that is 5. The current in a river is the motion of water along the direction of the river.

In other words, it is the flow of the water in the river. It is equally fine to use any of the last three equations to find the direction you need to point the boat.

If you use equation 2 or 4, you will need to find the speed of the boat relative to the ground v b , the opposite side before you can find the angle. Even though the speed of the boat relative to land v b is the unknown quantity, it is not the hypotenuse.

This is clear if you work from the drawing rather than focusing on which value is the unknown. For the angle I chose in the figure, the current is the adjacent side�it touches the angle. If you work with the other angle in the triangle, velocity of current is the opposite side and so you should use sine of that angle.

Remember that you are subtracting 1. You need to row faster than the boat actually travels, because some of your effort goes to countering the current. This problem asked you only to practice the math of working with vector components. A good double check is that no component is greater than the length of the vector, and that the shorter component is less than the longer one. It is also a good idea to go back to the picture to make sure that all of your values and directions make sense.

In this case, you were not given two vectors to add, but rather were given the sum and one component vector. It is much easier to work this problem correctly using a picture rather than focusing on the unknown quantities. In this case, you expect that the speed of the boat relative to land should be less than the speed at which you row it, because part of your efforts go to countering the current.

View Queries. How did you know the direction of the current? How did you know that V b and not V bw is in the y-direction?


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