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NCERT Solutions for Class 10 Maths Chapter 6 � Triangles � MathonGo

These ncert book chapter wise questions and answers are very helpful for CBSE board exam. By AAA criterion of similarity. By SSS criterion of similarity. These two triangles are not similar as they do not satisfy SAS criterion of similarity. In CDO, we. To Prove :. We have. Let AB the vertical pole and AC be its shadow. Also, foe DE be the vertical tower and DF be its shadow. Joined BC and EF.

By AA-similarity criterion. To prove :. By SAS-criterion of similarity. Ncert solution class 10 Maths includes text book solutions from Mathematics Ncert solutions for class 10 maths ch 6. Ques no. Plz rectify it.

Coward act. The Ncert Solutions For Class 10 Maths Ch 6 Key main question in this exercise Q14 is wrongly. The solution does not match that question but the site has just put up solution of Q12. Plz understand my suggestion so as to help other students avoid any deduction c valuable marks in boards. Hey in Q14 what you did is wrong�please read the question again n then post the answer it is completely different from Q There are ncert solutions for class 10 maths ch 6 20 � 30 comments complaining about question number I want to ask you a question that do you even read the solutionz Such act was not admirable from a educational site.

You shoul correct it. Howeverremaining answers was right. It helped me. Guyzz the q14 is right This is the property og side and median For ncert solutions for class 10 maths ch 6. About this property contact me At facebook page � Mukul Bhavesh. Guys first see and understand the question then make a comment. This was the website i trusted the most�.

Nd now its very clasd to see ncet mistake�students are here so that they can understand the sums�nd if here only mistake occurs, wat will the students learn??? Save my name, email, and website in this browser for the next time I comment. Download Now.

Do recheck. Question mathhs 14 is not solved correct please go through it. Cnert guys 14 question is wrong I was thinking that. Everything is fine but question no. Just copy pasted the 12th question. Q1 ka 4th wrong h becoz book mai solugions ki vo similar triangles h. Very very helpful for me� Thank uuuuuuu�??? Thank u very much for helping me!!!!!!!!!

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The partial pressure of ethane over a solution containing 6. If the solution contains 5. So there is expansion in volume on solution formation.

So weaker interactions are replaced by stronger interactions so , there is release of energy i. What is the molecular mass of the solute? At K, the vapour pressures of the two liquid components are What will be the vapour pressure of a mixture of The vapour pressure of water is Calculate vapour pressure of 1 molal solution of a non-volatile solute in it Sol: 1 molal solution of solute means 1 mole of solute in g of the solvent.

A solution containing 30g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2. Further, 18g of water is then added to the solution and the new of vapour pressure becomes 2. Calculate i molar mass of the solute.

When dissolved in 20g of benzene C 6 H 6 , 1 g of AB 2 lowers the freezing point by 2. The molar depression constant for benzene is 5. Calculate atomic masses of A and B. Suggest the most important type of intermolecular attractive interaction in the following pairs: i n-hexane and n-octane ii I 2 and CCl 4. Thus, the intermolecular interactions will be London dispersion forces.

Water is a polar molecule. Thus, the intermolecular interactions will be ion-dipole interactions. Thus, intermolecular interactions will be dipole-dipole interactions. Based on solute solvent interactions, arrange the following in order of increasing solubility in n-octane and explain.

Sol: n-octane C 8 H 18 is a non-polar liquid and solubility is governed by the principle that like dissolve like. Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water? Outside Delhi Sol:. If the solubility product of CuS is 6 x 10 , calculate the maximum molarity of CuS in aqueous solution. Nalorphene C 19 H 21 NO 3 , similar to morphine, is used to combat withdrawal symptoms in narcotic users.

Dose of nalorphene generally given is 1. Calculate the mass of 1. The depression in freezing point of water observed for the same amount of acetic acid, trichloroacetic acid and trifluoroacetic acid increases in the order given above.

Explain briefly. Solution: Fluorine being more electronegative than chlorine has the highest electron withdrawing inductive effect. Thus, triflouroacetic acid is the strongest trichloroacetic acid is second most and acetic acid is the weakest acid due to absence of any electron withdrawing group. Greater the extent of ionization greater is the depression in freezing point. The depression in the freezing point of water observed is 1.

Representation of Terms. Values of Terms. Students often have to write Class 10 Maths Ncert Solutions Chapter 5 on the basis of the formulas that they learn from the chapter. These formulas are:. This formula can be used for finding the class 10 maths chapter 5 NCERT solutions in which one needs to get the value of the nth term of an arithmetic progression.

The formula can be written as:. Here, a is the first term, d is the value of the common difference, n is the number of terms, and an is the nth term. Try to find out the nth term of the following arithmetic progression 1, 2, 3, 4, 5, �, an.

The total number of terms is This means that according to the formula, we can say that:. It should also be noted by students who refer to the NCERT Class 10 Maths Chapter 5 Solutions that the finite portion of an arithmetic progression is known as finite arithmetic progression. This means that the sum of a finite AP is known as an arithmetic series. The behaviour of the entire sequence will also depend on the values of the common difference.

This means that if the value of the common difference is positive, then the member terms will grow towards positive infinity. And if the value of the common difference is negative, then the member terms will move towards negative infinity.

One can easily calculate the sum of n terms of any known progression. For an arithmetic progression, it is possible to calculate the sum of the first n terms if the value of the first term and the total terms are known. The formula is mentioned below. But what if the value of the last term of the arithmetic progression is given? In that case, students should use the formula that is mentioned below.

For ease of revision, we have also summarized all the major formulas of this chapter in a table. That table is mentioned below. General Form of AP. The nth term of AP. Sum of n terms in AP. Sum of all terms in a finite AP with the last term as I.

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Chapter 15 - Probability. Class 10 is an important level for your academic excellence. This is the first time you will experience CBSE board exams held nationwide. Your performance will be determined by the depth of your knowledge and your answering skills. The exercises in the Class 10 Maths Chapter 2 have questions related to the new concepts you will learn. These questions in Chapter 2 Maths Class 10 have been designed to deliver a platform to judge your problem-solving skills.

You will need the best Maths Class 10 Chapter 2 Solutions for understanding the various approaches to solve the problems and prepare the chapter well. If you study Chapter 2 Class 10 Maths, you will discover concepts related to the geometrical meanings of polynomials. These simple answers to the exercise questions have been formatted by the experienced teachers.

They know where students generally feel confused.

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