Math Questions Answers | Solved Math Questions and Answers | Free Math Answers May 10, �� The formula says that the number of zeros at the end of n! is [ n / 5 ] + [ n /5^2 ] + [ n / 5^3 ] +, where [ ] means greatest integer function Here n = , so the answer is [ / 5 ] + [ Mar 24, �� Thanks for contributing an answer to Mathematics Stack Exchange! Please be sure to answer the question. Provide details and share your research! But avoid Asking for help, clarification, or responding to other answers. Making statements based on opinion; back them up with references or personal experience. Use MathJax to format equations. Oct 05, �� Answer: (d) More than 3. Question 2. If 1 is zero of the polynomial p(x) = ax 2 � 3(a � 1)x � 1, then the value of �a� is: (a) 1 (b) -1 (c) 2 (d) � 2 Answer: (a) 1. Question 3. If a, ? are zeroes of x 2 � 6x + k. What is the value of k if 3a + 2B = (a) � 16 (b) 8 (c) � 2 (d) -8 Answer: (a) � Question myboat319 boatplansted Reading Time: 3 mins.
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Once you know h and j, you know the quadratic factors of the quartic in y. Once you have factored the quartic into two quadratics, finishing the finding of the roots is simple, using the Quadratic Formula.

Use the long division method for polynomials. You know one zero is 2 so that means one term is x Divide P x by x-2 to get your answer. Answer Save. Favourite answer. Step 1 : One zero is 2, so x - 2 is a factor. Christine P Lv 5. Now, let's assume that d, f and g are all non-zero. Method 2 The quartic in y must factor into two quadratics with real coefficients, since any complex roots must occur in conjugate pairs.

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Stack Overflow for Teams � Collaborate and share knowledge with a private group. Create a free Team What is Teams? Learn more. Laurent series and Riemann zeros Ask Question. Asked 11 days ago. Active 11 days ago. Viewed 48 times. Bernard k 9 9 gold badges 58 58 silver badges bronze badges. Jose Garcia Jose Garcia 7, 2 2 gold badges 25 25 silver badges 47 47 bronze badges. Add a comment. Active Oldest Votes. Sign up or log in Sign up using Google.




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