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RS Aggarwal Solutions for Class 6 Maths Chapter 3-Whole Numbers To check Divisor ? Quotient + Remainder = Dividend ? + 0 = ? = = ? The other number is 6. On dividing by a certain number, the quotient is and the remainder is Find the divisor. Solution Given Dividend = Students can find CBSE Class 6 Maths Sample Paper Set 3 for free downloading in PDF. Solve it and get acquainted with the types of questions expected to be asked in the exam. RS Aggarwal Solutions for Class 6 Maths Chapter 3-Whole Numbers (d) ? is exactly divisible by 9 Here is the least number of 4 digits. Hence is exactly divisible by 9 Option (d) is the correct answer 3. The largest number of 6 digits which is exactly divisible by 16 is (a) (b) (c) (d) Solutions (a)
The sum of two consecutive odd numbers is always divisible by 4. RD Sharma Class 12 Solutions. Get the syllabus completed without leaving any flaws or weaknesses. Solution: Example 1: Take three consecutive numbers 20, 21 and We know that a number is divisible by 11 if the difference between the sum of the byjus class 6 maths chapter 3 kindle at odd places from the right and the sum of the digits at even places from the right of the number is either 0 or divisible by

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