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Arc: A piece of circle between two point is called arc. Segment: The region between a chord and either of its arcs is called a segment of circular region. Equal chords of a circle subtend equal angles at the centre. If the angles subtended by two chords of a circle at the Byjus App Class 9 Maths Us centre are equal, the chords are also equal.
The perpendicular from the centre of a circle to a chord bisects the chord. The line drawn through the centre of a circle to bisect a chord is perpendicular to the chord. There is one and only one circle passing through three non-collinear points. Because, between chord and arc a segment is formed. Sector is the region which is formed between radii and arc. Similarly, BD is diameter of circle. So, these solutions are applicable for all these boards also. All the questions are explained well using the theorems of circles and giving proper examples.
In few questions some axioms of circles are also used as theorems. Study Material for What do understand by a circle? What are the components of a circle? What are the main Properties related to a circle? Important Theorems on Circles Class 9 Maths Chapter 10 Equal chords of a circle are equidistant from the centre and cords equidistant from the centre of a circle are equal. Let the length of each side of the equilateral triangle be 2x.
A chord of a circle is equal to the radius of the circle, find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc. Solution: We have a circle having a chord AB equal to radius of the circle. Solution: The angle subtended by an arc of a circle at its centre is twice the angle subtended by the same arc at a point pn the circumference. In figure, A, B and C are four points on a circle. ABCD is a cyclic quadrilateral whose diagonals intersect at a point E.
Solution: Since angles in the same segment of a circle are equal. If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral, prove that it is a rectangle. If the non � parallel sides of a trapezium are equal, prove that it is cyclic. Two circles intersect at two points B and C. Solution: Since, angles in the same segment of a circle are equal.
If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side. They intersect at a point D, other than A. Let us join A and D. Thus, D lies on BC. Case � I: If both the triangles are in the same semi-circle.
Join BD. DC is a chord. Case � II : If both the triangles are not in the same semi-circle. Prove that a cyclic parallelogram is a rectangle. Since, ABCD is a cyclic quadrilateral. Thus, ABCD is a rectangle. Prove that the line of centres of two intersecting circles subtends equal angles at the two points of intersection. Two chords AB and CD of lengths 5 cm and 11 cm, respectively of a circle are parallel to each other and are on opposite sides of its centre.
If the distance between AB and CD is 6 cm, find the radius of the circle. Solution: We have a circle with centre O. Let r cm be the radius of the circle. The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at distance 4 cm from the centre, what is the distance of the other chord from the centre?
Parallel chords AB and CD are such that the smaller chord is 4 cm away from the centre. Let the vertex of an angle ABC be located outside a circle and let the sides of the angle intersect equal chords AD and CE with the circle. Proof: An exterior angle of a triangle is equal to the sum of interior opposite angles.
Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonals. Taking AB as diameter, a circle is drawn. A circle drawn with Q as centre, will pass through A, B and O. ABCD is a parallelogram. ABCE is a cyclic quadrilateral. AC and BD are chords of a circle which bisect each other. Similarly, AC is a diameter. Since, opposite angles of a parallelogram are equal.
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