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5. Evaluate the Given limit: Solution: Given limit: Substituting x = -1, we get = [(-1) Byjus Learning App Class 4 Maths Zero 10 + (-1) 5 + 1] / (-1 � 1) = (1 � 1 + 1) / � 2 = � 1 / 2. 6. Evaluate the Given limit: Solution: Given limit: = [(0 + 1) 5 � 1] / 0 =0. Since, this limit is undefined. Substitute x + 1 = y, then x = y � 1. 7. Evaluate the Given limit: Solution: 8. Evaluate the Given limit. JEE Main Maths Limits, Continuity and Differentiability Previous Year Questions With Solutions. lim ? h > 0 2 (a + h) sin ? (a + h) + (a + h) 2 cos ? (a + h) 1. = 2 a sin ? a + a 2 cos ? a. Hence, the limit doesn�t exist. = lim ? x > 0 (1 + tan ? x 1 ? tan ? x) 1 / x = lim ? x > 0 { (1 + tan ? x) 1 / tan ? x } (tan ? x) / x { (1 ? tan ? x) 1 / tan ? x } (tan ? x) / x = e e ? 1 = e 2. Free Create With Maths- Standard 0 - Videos and Practice Questions to help you crack your exams.

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